Ajutorrrr!AM NEVOIE DE REZOLVAREA ACESTOR SUBPUNCTE a,b,c,d,e,f URGENTT!DAU COROANA PRIMULUI RASPUNS COMPLET

d)x^2 - 4 + 6 = 4x^2 - 12x + 9 - 3x^2 + 3x
x^2 + 2 = x^2 - 9x + 9
2 = -9x + 9
-7 = -9x
x = 7/9

e)1 - x = 2x - x^2 + 3x + x^2 - 8x + 16
1 - x = -3x + 16
2x = 15
x = 15/2

f)-x - (4x^2 + 12x + 9) = -4x^2 - 3x + 6
-x - 4x^2 - 12x - 9 = -4x^2 - 3x + 6
-13x - 9 = -3x + 6
-10x = 15
x = -15/10 = -3/2

b)2x - 6 - 5x = 6 - 3x - 12
-3x - 6 = -3x - 6 ecuație fără sens

c)x - 2(x^2 - 6x + 9) = 3x - 2x^2 + 3 - 2x
x - 2x^2 + 12x - 18 = -2x^2 + x + 3
13x - 18 = x + 3
12x = 21
x = 21/12 = 7/4

b)

2(x-3)-5x=6-3(x+4)

2x-6-5x=6-3x-12

-3x-6=6-3x-12

-3x-6=-3x-6

c)

x-2(x-3)²=(x+1)(3-2x)

x-2x²+12x-18=3x-2x²+3-2x

13x-2x²-18=3x-2x²+3-2x

13x-2x²-18=x-2x²+3

13x-18=x+3

13x=x+3+18=x+21

13x-x=21

12x=21

[tex]x = \frac{21}{12} = \frac{7}{4} [/tex]

d)

(x-2)(x+2)+6=(2x-3)²-3x(x-1)

x²-2²+6=4x²-12x+9-3x²+3x

x²-4+6=4x²-12x+9-3x²+3x

x²+2=4x²-12x+9-3x²+3x

x²+2=x²-9x+9

2=-9x+9

2-9=-9x

-7=-9x

[tex] \frac{ - 7}{ - 9} = x \\ \\ \frac{7}{9} = x \\ \\ x = \frac{7}{9} [/tex]

e)

1-x=2x-(x-3)•x+(x-4)²

1-x=2x-x(x-3)+(x-4)²

1-x=2x-x²+3x+x²-8x+16

1-x=-3x+16

-x=-3x+16-1=-3x+15

-x+3x=15

2x=15

[tex]x = \frac{15}{2} [/tex]

f)

-x-(-2x-3)²=-4x²-3(x-2)

-x-4x²-12x-9=-4x²-3x+6

-13x-4x²-9=-4x²-3x+6

-13x-9=-3x+6

-9=-3x+6+13x=10x+6

-9-6=10x

-15=10x

[tex] - \frac{15}{10} = x \\ \\ - \frac{3}{2} = x \\ \\ x = - \frac{3}{2} [/tex]