[tex] \frac{x + 3}{4} + \frac{x - 2}{3} = \: \frac{x + 1}{2} [/tex]


Răspuns :


[tex] \frac{x + 3}{4} + \frac{x - 2}{3} = \frac{x + 1}{2} \\ \\ 3(x + 3) = 4(x - 2) = 6(x + 1) \\ \\ 3x + 9 + 4x - 8 = 6x + 6 \\ \\ 7x + 1 = 6x + 6 \\ \\ 7x = 6x + 6 - 1 \\ \\ 7x = 6x + 5 \\ \\ 7x - 6x = 5 \\ \\ x = 5 [/tex]