Care este rezultatul calculului 2×10^(-2)×80/16×10^(-19)

Răspuns :


[tex] \frac{2 \times 10 {}^{ - 2} \times 80 }{16 \times 10 {}^{ - 19} } = \frac{160 \times 10 \ {}^{ - 2} }{16 \times 10 {}^{ - 19} } = \frac{10 \times 10 {}^{ - 2} }{10 {}^{ - 19} } = \frac{10 {}^{ - 1} }{10 {}^{ - 19} } = \frac{ \frac{1}{10} }{10 {}^{ - 19} } = \frac{1}{10 \times 10 {}^{ - 19} } = \frac{1}{10 {}^{ - 18} } = \frac{1}{ \frac{1}{10 {}^{18} } } = \frac{10 {}^{18} }{1} [/tex]