a = 6, b = 3, c = 8
Delta = b²-4ac = 9 - 4*6*8 = 9-192 = -183 <0
=> x nu apartine lui lR
Cum am obtinut delta negativa, e clar ca ecuatia are radacini in multimea nr complexe (C).
=> x1 = (-b+ i√-delta)/2a = (-3+i√-(-183))/12 = (-3+i√183)/12
x2 = (-3 - i√183)/12
