daca a+b=1450b+c=1231,iara+c=2242,afla dublul sumei celor 3numere.

Răspuns :

a+b+b+c+c+a=2a+2b+2c=2(a+b+c)  =>

a+b+a+c+c+a=

1450+1231+2242=4923

=>2(a+b+c)=4923

sper ca te-am ajutat

3a +3b +3c=1450+1231+2242=2681+2242= 4923 4923:3=1414 1414×2=2828