100g xg yg
Al2( CO3)3 = Al2O3 +3 CO2
234g 102g 3.44g
MAl2(CO3)3 =2 .27+3.12+ 9.16=234------>1mol=234g
MAl2O3=2.27 +3.16=102 ------->1mol=102g
MCO2=12+2.16=44----->1mol=44g
x=100.102 :234=43,58 g Al2 o3
y=100.3.44:234=56,41 g CO2
n=nr.moli
n=m: M
n=56,41 g : 44g/moli=1,28 moli CO2