a=6+radical din 11
b=6-radical din 11
Calculati;
(a-b-1-2radical din 11)^2018


Răspuns :

[tex]a = 6 + \sqrt{11} [/tex]

[tex]b = 6 - \sqrt{11} [/tex]

[tex] {(a - b - 1 - 2 \sqrt{11} )}^{2018} [/tex]

[tex] = {[6 + \sqrt{11} - ( 6- \sqrt{11} ) - 1 - 2 \sqrt{11} ]}^{2018} [/tex]

[tex] = {(6 + \sqrt{11} - 6 + \sqrt{11} - 1 - 2 \sqrt{11}) }^{2018} [/tex]

[tex] = {(6 - 6 + \sqrt{11} + \sqrt{11} - 2 \sqrt{11} - 1 )}^{2018} [/tex]

[tex] = {(2 \sqrt{11} - 2 \sqrt{11} - 1)}^{2018} [/tex]

[tex] = {( - 1)}^{2018} [/tex]

[tex] = 1[/tex]