n : 9 = a rest 5 => n = 9a + 5
n : 7 = b rest 5 => n = 7b + 5
n : 21 = c rest 5 => n = 21c + 5
9 = 3^2
7 = 7
21 = 3 × 7
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cmmmc = 3^2 × 7 = 9 × 7 = 63
63 + 5 = 68 < 150 ; convine
M63 + 5 = 63×2 + 5 = 131 < 150 ; convine
M63 + 5 = 63 × 3 + 5 = 194 > 150; nu convine
asadar avem 2 numere naturale care respecta conditiile cerintei :
68 si 131
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