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Răspuns :

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Vezi imaginea 102533

f:R→R a.i. f(x)=ax +b .

f(4)=4a+b dar f(4)=8 => 4a+b =8 .

f(1)+f(2)+f(3)=a+b+2a+b+3a+b=6a+3b dar f(1)+f(2)+f(3)=6a+2b => b=0 .

4a=8 => a=2 => f(x)=2x .