Rezolvati in Q ecuatile 2x+5 supra 3 + 0,5 = x-4 supra 6

[tex] \frac{2x + 5}{3} + 0,5 = \frac{x - 4}{6} \\ \\ \frac{2x + 5}{3} + \frac{1}{2} = \frac{x - 4}{6} \\ \\ 6 \times \frac{2x + 5}{3} + 6 \times \frac{1}{2} = 6 \times \frac{x - 4}{6} \\ \\ 2(2x + 5) + 3 = x - 4 \\ \\ 4x + 10 + 3 = x - 4 \\ \\ 4x + 13 = x - 4 \\ \\ 4x - x = - 4 - 13 \\ \\ 3x = - 17 \\ \\ 3x : 3 = - 17 : 3 \\ \\ x = - 17 : 3 = - \frac{17}{3} [/tex]

(2x + 5 )/3 + 0,5 = (x-4)/6;

4x + 10 + 3 = x -4;

3x = - 17;

x = - 17/3 = - 5,(6).