11-(7+6-9)+a+b=15,iar a si b sunt numere consecutive impare;

11 - ( 7 + 6 - 9 ) + a + b = 15

11 - ( 13 - 9 ) + a + b = 15

11 - 4 + a + b = 15

7 + a + b = 15

a + b = 15 - 7

a + b = 8

b = a + 2 → numar impar

a + ( a + 2 ) = 8

2 × a = 8 - 2

2 × a = 6

a = 6 : 2 ⇒   a = 3

b = 3 + 2 ⇒   b = 5

11-(7+6-9)+a+b = 15 ; 11-4+a+b = 15 ; a+b = 15-7 = 8 ; b = a+2 inlocuim a

a+a+2 = 8 ; 2a = 8-2 = 6 ; a = 6:2 = 3 ; b = 3+2 =5 ;

numerele sunt 3 si 5 ;