a=((3\sqrt2-2\sqrt30) ^{2})-11
a=?


Răspuns :


[tex] {(3 \sqrt{2} - 2 \sqrt{30} ) }^{2} - 11 = {(3 \sqrt{2}) }^{2} - 12 \sqrt{60} + {(2 \sqrt{30}) }^{2} - 11 = 18 - 12 \sqrt{60} + 120 - 11 = 127 - 48 \sqrt{15} \\ a = 127 - 48 \sqrt{15} [/tex]