Fie a,b,c cantitatile din cele 3 zile si T totalul. Astfel ca vom avea
a+b+c=T
a=2/7 T
b=13/25(T-a)+379 kg
c=2561 kg
Inlocuim ce stim in prima relatie:
2/7 T + 13/25(T-a)+379 kg +2561 kg =T
2/7 T + 13/25T-13/25(2/7 T)+379 kg +2561 kg =T
2/7 T + 13/25T-26/175 T +2940=T
2940 = T-2/7 T -13/25T+26/175 T
(Vom aduce la acelasi numitor adica 175)
2940 kg= (175 T -50T-91T+26)/175
2940*175 kg = T(125-91+26)
T= 2940*175/60=49*175=8575 kg
