alcool monohidroxilic saturat = CnH2n+1OH
100%...............................26,66% O2
14n+18.............................. 16
=> 26,66(14n+18) = 1600
=> n = 3 => C3H7OH
2,3 g .... md .................... V L
C3H7OH + Na => C3H7ONa + 1/2H2
23 ............60 ................. 22,4/2
=> md = 60x2,3/23 = 6 g propanoxid de Na
c% = 20% , c% = mdx100/ms => ms = mdx100/c% = 6x100/20 = 300 g sol
=> V = 2,3x11,2/23 = 1,12 L H2