Determinati perechea (a,b) de numerele reale

Determinati Perechea Ab De Numerele Reale class=

Răspuns :

[tex]\frac{2-i}{3+i}= \frac{(2-i)(3-i)}{(3+i)(3-i)}=\frac{6-2i-3i+i^2}{9-i^2}=\frac{6-5i-1}{9-(-1)}=\frac{5-5i}{10}=\frac{5}{10}-\frac{5i}{10}=\frac{1}{2}-\frac{i}{2}[/tex]

[tex]a=\frac{1}{2}[/tex]

[tex]b=-\frac{1}{2}[/tex]