Descompuneti in factori x la a 2 - 8x plus 12

Răspuns :

x²-8x+16-4=(x-4)²-2²=(x-4-2) (x-4+2) =(x-6)(x-2)

sau  clasic

x²-6x-2x+12= x(x-6) -2(x-6) =(x-6) (x-2)


x² - 8x + 12 =

= x² - 2x - 6x + 12

= x(x - 2) - 6(x - 2)

= (x - 6)(x - 2)