Fie x lungimea drumului
x/4 -> a parcurs in prima zi
x-x/4=3x/4 -> a ramas de parcurs dupa prima zi
3x*2/4*3=6x/12=x/2 -> a parcurs in a doua zi
3x/4-x/2=x/4-> a ramas de parcurs dupa a doua zi
x/4*2=x/8 -> a parcurs in a treia zi
x=x/8+x/2+x/4+60
x=60+(x+4x+2x)/8
x=60+7x/8
7x/8-x=-60
(7x-8x)/8=-60
-x/8=-60
x=8*60
x=480 km ->lungimea totala a drumului
x/4=480/4=120 km ->a parcurs in prima zi
x/2=480/2=240 km ->a parcurs in a doua zi
x/8=480/8=60 km_ a parcurs in a treia zi
60 km-> in a patra zi
