Cati izomeri cu catena liniara are compusul C3H4Cl2

Răspuns :

CaHbOcNdXe

NE = (2a+2)-(b-d+e)/2 = (2×3+2)-(4+2)/2 = 8-6/2 = 2/2 = 1 leg. dubla

CH2=C(Cl)-CH2Cl - 1,2-dicloro-1-propena

ClCH2-CH=CHCl - 1,3-dicloro-1-propena