Rezultatul calculului (1 supra 12-1 supra 18)×9-1,25! Va rog

(1/6)(1/2-1/3)*9-1-0,25=
(1/6)(1/6) *9-1-0,25=
9/36-1-1/4=
1/4-1-1/4=
=-1

[tex] \it ( ^{3)} \frac{1}{12} \: - \: ^{2)} \frac{1}{18} ) \cdot 9 - 1,25 = \\ \\ \it ( \frac{3}{36} - \frac{2}{36} ) \cdot 9 - \frac{125}{100} = \\ \\ \it \frac{1}{36} \cdot 9 - \frac{125}{100} = \\ \\ \it \frac{9}{36} - \frac{125}{100} = \frac{1}{4} - \frac{5}{4} = - \frac{4}{4} ^{(4} = \boxed{- 1}[/tex]