X la puterea 7/3 DERIVAT!!!!!

   
[tex]\displaystyle\\ \text{Folosim formula:}\\\\ \text{Daca }~f(x)=x^{\b a},~~a \in R,~~\text{atunci}~~f'(x) = ax^{(\b a-\b 1)}\\\\ \left(x^{ \left(\frac{7}{3}\right)}\right)'= \frac{7}{3}x^{\left(\frac{7}{3}-1 \right)}= \boxed{ \frac{7}{3}x^{\left(\frac{4}{3} \right)} }[/tex]

[tex]\left(x^{^{\dfrac{7}{3}}}\right)'= \dfrac{7}{3}\cdot x^{^\Big{\dfrac{7}{3}-1}} = \dfrac{7}{3}\cdot x^{^{\dfrac{7-3}{3}}} = \dfrac{7}{3}\cdot x^{^{\dfrac{4}{3}}}[/tex]