log(3)x=2log(3)4+log(3)2-1/2log(3)16

\log _{10}\left(3\right)x=2\log _{10}\left(3\right)\cdot \:4+\log _{10}\left(3\right)\cdot \:2-\frac{1}{2}\log _{10}\left(3\right)\cdot \:16=
2\log _{10}\left(3\right)\cdot \:4=8\log _{10}\left(3\right)=\frac{1}{2}\log _{10}\left(3\right)\cdot \:16=8\log _{10}\left(3\right)=\log _{10}\left(3\right)x=8\log _{10}\left(3\right)+2\log _{10}\left(3\right)-8\log _{10}\left(3\right)=\log _{10}\left(3\right)x=2\log _{10}\left(3\right)
\begin{x=2}