Calculati:

a) (-3) la puterea 101 + 3 la puterea 101=?
b)(-2) la puterea 3 +(-1001) la puerea 0-3 la puterea 2=?
c)(-343) la puterea 7 ori 7 la puerea 23 : (-49) la puterea 21 =?
d)[(-5) la puterea 2 totul la puterea 5 : 125 la puerea 3=? 

URGENTTT!


Răspuns :

[tex]a) {( - 3)}^{101} + {3}^{101} = 0[/tex]

[tex]b) {( - 2)}^{3} + {( - 1001)}^{0} - {3}^{2} = - 8 + 0 - 9 = - 17[/tex]

[tex]c) {( - 343)}^{7} \times {7}^{23} \div {( - 49)}^{21} [/tex]

[tex] = { {( - 7}^{3} )}^{7} \times {7}^{23} \div { {( - 7}^{2} )}^{21} [/tex]

[tex] = {( - 7)}^{3 \times 7} \times {7}^{23} \div {( - 7)}^{2 \times 21} [/tex]

[tex] = {( - 7)}^{21} \times {7}^{23} \div {( - 7)}^{42} [/tex]

[tex] = - ( {7}^{21} \times {7}^{23} ) \div {( - 7)}^{42} [/tex]

[tex] = { - 7}^{21 + 23} \div {( - 7)}^{42} [/tex]

[tex] = { - 7}^{44} \div {( - 7)}^{42} [/tex]

[tex] = {( - 7)}^{44 - 42} [/tex]

[tex] = {( - 7)}^{2} [/tex]

[tex] = 49[/tex]

[tex]d) {( { - 5}^{2}) }^{5} \div {125}^{3} [/tex]

[tex] = {( - 5)}^{2 \times 5} \div { {(5}^{3} )}^{3} [/tex]

[tex] = {( - 5)}^{10} \div {5}^{3 \times 3} [/tex]

[tex] = {( - 5)}^{10} \div {5}^{9} [/tex]

[tex] = - ( {5}^{10} \div {5}^{9} )[/tex]

[tex] = - {5}^{10 - 9} [/tex]

[tex] = - {5}^{1} [/tex]

[tex] = - 5[/tex]