cazuri posibile
Combinaride 10 luate cate 6=10!/6!/4!=7*8*9*10/8*3=210
cazuri favorabile
consideram cele 6 numere ordonate descrescator
ele pot fi {9;8 a;b;c;d} in care abcd apartin lui Combinaride 7 (numere mai micidecat 8) luatecate 4
sau {10;8 ;a;b.c;d} combinaride 7 (num mai mici decat 8 )luate cate 4
Comb de 7 luatecate 4=7!/4!*3!=5*6*7/6=35
P = nr caz fav /nr caz posib= (35+35)/210=70/210=1/3
