Calculati:
2supra 3+4 supra 3=
b)13 supra 9+4 supra 9+1 supra 9;
c)17 supra 8-5 supra 8=;
d)41 supra 7 -5 supra 7-8 supra 7=;
e)3 supra 4 × 8 supra 9=;
f)15 supra 11 ×2 supra 3×22 supra 5=;
g)15 supra 22:20 supra11=;
h)35 supra 33:5 supra 11:7 supra3;
DAu CORONITA!!!

[tex] a)\frac{2}{3} + \frac{4}{3} = \frac{2 + 4}{3} = \frac{6}{3} = 2 \\ \\ b) \frac{13}{9} + \frac{4}{9} + \frac{1}{9} = \frac{13 + 4 + 1}{9} = \frac{18}{9} = 2 \\ \\ c) \frac{17}{8} - \frac{5}{8} = \frac{17 - 5}{8} = \frac{12}{8} = \frac{3}{2} \\ \\ d) \frac{41}{7} - \frac{5}{7} - \frac{8}{7} = \frac{41 - 5 - 8}{7} = \frac{28}{7} = 4 \\ \\ e) \frac{3}{4} \times \frac{8}{9} = \frac{3 \times 8}{4 \times 9} = \frac{24}{36} = \frac{2}{3} \\ \\ f) \frac{15}{11} \times \frac{2}{3} \times \frac{22}{5} = \frac{15 \times 2 \times 22}{11 \times 3 \times 5} = \frac{660}{165} = 4 \\ \\ g) \frac{15}{22} : \frac{20}{11} = \frac{15}{22} \times \frac{11}{20} = \frac{15 \times 11}{22 \times 20} = \frac{165}{440} = \frac{3}{8} \\ \\ h) \frac{35}{33} : \frac{5}{11} : \frac{7}{3} = \frac{35}{33} \times \frac{11}{5} \times \frac{3}{7} = \frac{35 \times 11 \times 3}{33 \times 5 \times 7} = \frac{1155}{1155} = 1 [/tex]