dacă x+3 supra x-2 = 1 pe 2 , atunci x = ?

Aceasta ar fi rezolvarea.

[tex] \frac{x + 3}{x - 2} = \frac{1}{2} \\ \\ x + 3 = \frac{1}{2}(x - 2) \\ \\ x + 3 = \frac{x - 2}{2} \\ \\ x + 3 = - 1 + \frac{x}{2} \\ \\ x + 3 = \frac{x}{2} - 1 \\ \\ 2x + 6 = x - 2 \\ \\ 2x + 6 - x = - 2 \\ \\ x + 6 = - 2 \\ \\ x = - 2 - 6 = - 8 [/tex]