[tex] {2}^{1} \times {2}^{2} \times {2}^{3} \times {2}^{4} \times .... {2}^{45} [/tex]
Va rog dau coroana


Răspuns :

2^(1+2+...+45)=2^(45*46/2)=2^1035

Dam factor 2^1 = 2^(1+2+3+...+45) Pt. suma de la exponent aplic formula sumei lui Gauss => 45*46/2 = 1035 Inlocuim => 2^1035