Am nevoie de ajutor la problema!!!

-calculez masa si moli NaOH din solutie

c=mdx100/ms---> md= 40x500/100g= 200g NaOH        \M,NaOH= 40g/mol

niu= m/M= 200G/40g/mol= 5mol NaOH

m,apa= ms-md= 500g-200g=300g

-din ecuatia chimica,deduc celelalte mase si moli

1mol....   ..1mol..........1mol.....1mol                        M,HCl= 36,5g/mol,M,NaCl=58,5g/mol

NaOH   +  HCl---> NaCl +    H2O                      M,H2O=18g/mol

5mol......x=5mol....y=5mol...z=5mol

m,HCl= niuxM= 5X36,5 g=.....................calculeaza

m,NaCl= 5x58,5 g=....................

m,apa= 5x18 g=90g

m,totala de apa=m,apa din reactie + m,apa ramasa din sol NaOH

                          = 90+300g=390g